1/(27^(1-5x))=81^(3x-11)

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Solution for 1/(27^(1-5x))=81^(3x-11) equation: 



1/(27^(1-5x))=81^(3x-11)

We move all terms to the left:

1/(27^(1-5x))-(81^(3x-11))=0



Domain of the equation: (27^(1-5x))!=0

x∈R



We add all the numbers together, and all the variables

1/(27^(-5x+1))-(81^(3x-11))=0

We multiply all the terms by the denominator


-((81^(3x-11)))*(27^(-5x+1))+1=0



We calculate terms in parentheses: -((81^(3x-11)))*(27^(-5x+1)), so:

(81^(3x-11)))*(27^(-5x+1)



We calculate terms in parentheses: +(81^(3x-11)))*(27^(-5x+1), so:

81^(3x-11)))*(27^(-5x+1

We add all the numbers together, and all the variables

-5x+81^(3x-11)))*(27^(+1

Back to the equation:

+(-5x+81^(3x-11)))*(27^(+1)



We add all the numbers together, and all the variables

(-5x+81^(3x-11)))*(27^1

Back to the equation:

-((-5x+81^(3x-11)))*(27^1)



We move all terms containing x to the left, all other terms to the right

-((-5x+81^(3x-11)))*27^1=-1

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